因数 6a^2+(9a+1)

解

因数

6 a^{2} + (9 a + 1)

6 (a - \frac{- 9 + 57}{12}) (a - \frac{- 9 - 57}{12})

解答ステップ

6 a^{2} + (9 a + 1)

括弧を削除する:

(a) = a

= 6 a^{2} + 9 a + 1

書き換え

= 6 (a^{2} + \frac{3 a}{2} + \frac{1}{6})

因数

a^{2} + \frac{3 a}{2} + \frac{1}{6} : (a - \frac{19 - 3 3}{4 3}) (a - \frac{- 3 3 - 19}{4 3})

6 (a - \frac{19 - 3 3}{4 3}) (a - \frac{- 3 3 - 19}{4 3})

\frac{- 3 3 + 19}{4 3} = \frac{- 9 + 57}{12}

= 6 (a - \frac{57 - 9}{12}) (a - \frac{- 3 3 - 19}{4 3})

\frac{- 3 3 - 19}{4 3} = \frac{- 9 - 57}{12}

= 6 (a - \frac{57 - 9}{12}) (a - \frac{- 9 - 57}{12})