展开 (x+Δx)^2-4(x+Δx)

解答

展开

(x + Δ x)^{2} - 4 (x + Δ x)

x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x

求解步骤

(x + Δ x)^{2} - 4 (x + Δ x)

乘开

- 4 (x + Δ x) : - 4 x - 4Δ x

= (x + Δ x)^{2} - 4 x - 4Δ x

(x + Δ x)^{2} : x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x

e x p an d \frac{( x + 2 ) ( x + 5 )}{( x + 6 ) ( x + 7 )}

e x p an d sin (w (t - 2))

e x p an d \frac{x ( 3 x - 1 )}{( x + 1 ) ^{2}}

e x p an d (4 e - 3 f)^{3}

e x p an d (2 e^{3 x} + e^{- 3 x})^{2}