展开 (4x^2+2x-30)(2x-5)

解答

展开

(4 x^{2} + 2 x - 30)^{\circ} (2 x - 5)

2 x (4 x^{2} + 2 x - 30)^{\circ} - 5 (4 x^{2} + 2 x - 30)^{\circ}

求解步骤

(4 x^{2} + 2 x - 30)^{\circ} (2 x - 5)

= (2 x - 5) (4 x^{2} + 2 x - 30)^{\circ}

使用分配律:

a (b - c) = ab - a c

a = (4 x^{2} + 2 x - 30)^{\circ}, b = 2 x, c = 5

= (4 x^{2} + 2 x - 30)^{\circ} \cdot 2 x - (4 x^{2} + 2 x - 30)^{\circ} \cdot 5

= 2 x (4 x^{2} + 2 x - 30)^{\circ} - 5 (4 x^{2} + 2 x - 30)^{\circ}

e x p an d - \frac{x ( - a - m )}{y}

e x p an d \frac{x ( x - 5 ) ( x - 8 )}{2}

e x p an d \frac{1}{s ( s ^{2} + s + 1 )}

e x p an d \frac{e ^{x} ( 1 - cos ( x ) )}{x}

e x p an d m (- n) + mn