erweitern (f(2x^2+2x^2h-1))/h

Lösung

erweitern

\frac{f ( 2 x ^{2} + 2 x ^{2} h - 1 )}{h}

\frac{2 f x ^{2}}{h} + 2 f x^{2} - \frac{f}{h}

Schritte zur Lösung

\frac{f ( 2 x ^{2} + 2 x ^{2} h - 1 )}{h}

Multipliziere aus

f (2 x^{2} + 2 x^{2} h - 1) : 2 f x^{2} + 2 f x^{2} h - f

= \frac{2 f x ^{2} + 2 f x ^{2} h - f}{h}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 f x ^{2} + 2 f x ^{2} h - f}{h} = \frac{2 f x ^{2}}{h} + \frac{2 f x ^{2} h}{h} - \frac{f}{h}

= \frac{2 f x ^{2}}{h} + \frac{2 f x ^{2} h}{h} - \frac{f}{h}

Streiche

\frac{2 f x ^{2} h}{h} : 2 f x^{2}

= \frac{2 f x ^{2}}{h} + 2 f x^{2} - \frac{f}{h}

e x p an d (3 x^{2} + 5 x - 2)^{5}

e x p an d \frac{( x - y ) ^{3}}{( x + y ) ^{2}}

e x p an d 2 (x^{3} e^{- 3 x} - 3)

e x p an d (5 e^{2} - 2 b + c^{3}) (3 x - 2 y - 5 z + 2)

e x p an d \frac{b}{s ( s + a )}