erweitern (32(x+1)(2x+1))/(3x^2)

Lösung

erweitern

\frac{32 ( x + 1 ) ( 2 x + 1 )}{3 x ^{2}}

\frac{64}{3} + \frac{32}{x} + \frac{32}{3 x ^{2}}

Schritte zur Lösung

\frac{32 ( x + 1 ) ( 2 x + 1 )}{3 x ^{2}}

Multipliziere aus

32 (x + 1) (2 x + 1) : 64 x^{2} + 96 x + 32

= \frac{64 x ^{2} + 96 x + 32}{3 x ^{2}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 x ^{2} + 96 x + 32}{3 x ^{2}} = \frac{64 x ^{2}}{3 x ^{2}} + \frac{96 x}{3 x ^{2}} + \frac{32}{3 x ^{2}}

= \frac{64 x ^{2}}{3 x ^{2}} + \frac{96 x}{3 x ^{2}} + \frac{32}{3 x ^{2}}

Streiche

\frac{64 x ^{2}}{3 x ^{2}} : \frac{64}{3}

= \frac{64}{3} + \frac{96 x}{3 x ^{2}} + \frac{32}{3 x ^{2}}

Streiche

\frac{96 x}{3 x ^{2}} : \frac{32}{x}

= \frac{64}{3} + \frac{32}{x} + \frac{32}{3 x ^{2}}

e x p an d (x + d x) (- y cos (x))

e x p an d - 1 (a + b = x + 2) - 1

e x p an d - \frac{1}{s ^{2} ( s + 1 )}

e x p an d ((e^{x} - e^{- x}))^{2}

e x p an d y (I n y^{2} - V y + 1) V d x + x d V - V y d y