erweitern ((2x+1)(3x+1))/6

Lösung

erweitern

\frac{( 2 x + 1 ) ( 3 x + 1 )}{6}

x^{2} + \frac{5 x}{6} + \frac{1}{6}

Schritte zur Lösung

\frac{( 2 x + 1 ) ( 3 x + 1 )}{6}

Multipliziere aus

(2 x + 1) (3 x + 1) : 6 x^{2} + 5 x + 1

= \frac{6 x ^{2} + 5 x + 1}{6}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 5 x + 1}{6} = \frac{6 x ^{2}}{6} + \frac{5 x}{6} + \frac{1}{6}

= \frac{6 x ^{2}}{6} + \frac{5 x}{6} + \frac{1}{6}

Teile die Zahlen:

\frac{6}{6} = 1

= x^{2} + \frac{5 x}{6} + \frac{1}{6}

e x p an d \frac{x ^{2} - 1}{3 ( 2 x - 1 )}

e x p an d 2 a C e^{a t} (1 + b C e^{a t})

e x p an d \frac{2}{( 1.96 ) ^{4}}

e x p an d (24 x y - 6 x^{2} y - 4 x y^{2}) d x

e x p an d e^{x} \cdot (1 + e^{- x})^{2}