展开 (x^2+3x-6)\circ (3x-7)

解答

展开

(x^{2} + 3 x - 6) \circ (3 x - 7)

3 \circ x^{3} + 2 \circ x^{2} - 39 \circ x + 42 \circ

求解步骤

(x^{2} + 3 x - 6) \circ (3 x - 7)

= \circ (x^{2} + 3 x - 6) (3 x - 7)

乘开

(x^{2} + 3 x - 6) (3 x - 7) : 3 x^{3} + 2 x^{2} - 39 x + 42

= \circ (3 x^{3} + 2 x^{2} - 39 x + 42)

乘开

\circ (3 x^{3} + 2 x^{2} - 39 x + 42) : 3 \circ x^{3} + 2 \circ x^{2} - 39 \circ x + 42 \circ

= 3 \circ x^{3} + 2 \circ x^{2} - 39 \circ x + 42 \circ

e x p an d \frac{x + 5}{( x ^{2} + 1 ) ^{2} ( x - 3 )}

e x p an d e^{{- y}}

e x p an d \frac{1}{( 1 + x ^{2} ) arctan ( x )}

e x p an d, 0.5 (110 - 2 p) (\frac{110 - 2 p}{2})

\frac{d}{d t} ((x) (3 t - 5))