展開する (10x+7y+3z=7,)(10x+7x+3x=10)

解

展開する

(10 x + 7 y + 3 z = 7,) (10 x + 7 x + 3 x = 10)

200 x^{2} = 10

解答ステップ

(10 x + 7 y + 3 z = 7,) (10 x + 7 x + 3 x = 10)

= (10 x + 7 y + 3 \cdot 7 =, z) (10 x + 7 x + 3 \cdot 10 = x)

括弧を分配する

10 x \cdot 10 x + 10 x \cdot 7 x + 10 x \cdot 3 x = 10 + 7 y \cdot 10 x + 7 y \cdot 7 x + 7 y \cdot 3 x = 10 + 3 z = 7, 10 x + 3 z = 7, 7 x + 3 z = 7, 3 x = 10

10 \cdot 10 xx + 10 \cdot 7 xx + 10 \cdot 3 xx = 10 + 7 \cdot 10 x y + 7 \cdot 7 x y + 7 \cdot 3 x y = 10 + 3 z = 7, 10 x + 3 z = 7, 7 x + 3 z = 7, 3 x = 10

拡張

10 \cdot 10 xx + 10 \cdot 7 xx + 10 \cdot 3 xx : 200 x^{2}

200 x^{2} = 10