展开 (2,0,-1)*(1,-2,4)'

解答

展开

(2, 0, - 1) \cdot (1, - 2, 4)^{'}

2 (1, - 2 \cdot 4,)', 0, - 1 (1, - 2 \cdot 4,)'

求解步骤

(2, 0, - 1) (1, - 2, 4)^{'}

= (2 \cdot 0,, - 1) (1, - 2 \cdot 4,)^{^{'}}

使用分配律:

a (b - c) = ab - a c

a = (1, - 2, 4)^{'}, b = 2, 0,, c = 1

= (1, - 2, 4)^{^{'}} 2, 0, - (1, - 2, 4)^{^{'}} 1

= 2 (1, - 2 \cdot 4,)^{^{'}}, 0, - 1 (1, - 2 \cdot 4,)^{^{'}}

e x p an d (\frac{600 ( 520 - x )}{( x )}) - 345

e x p an d + 1 - (x + 4 y^{2}) \cdot d y + d y d x

e x p an d (3 e^{2} + 5 y) (2 e^{3} + 8 z)

e x p an d \frac{d}{d x} ((2 - x) e^{x}) + 2 - x

e x p an d - 5 (2 x + 2 y = - 20)