展开 2-3(x+Δx)

解答

展开

2 - 3 (x + Δ x)

2 - 3 x - 3Δ x

求解步骤

2 - 3 (x + Δ x)

乘开

- 3 (x + Δ x) : - 3 x - 3Δ x

= 2 - 3 x - 3Δ x

e x p an d \frac{1 - 6 x}{x ^{2} ( 2 x - 1 )}

f a c t or 30 (4 x^{5} + x)^{29} (20 x^{4} + 1)

e x p an d \frac{16}{s ( s + 1 ) ( s + 5 )}

e x p an d \frac{t ( s - 1 )}{s ( s ^{2} - s - 2 )}

e x p an d (x + x u^{2} - 1) x d u