erweitern (xz^'+z)(2z+1)

Lösung

erweitern

(x z^{^{'}} + z) (2 z + 1)

2 x z^{1 +'} + x z^{'} + 2 z^{2} + z

Schritte zur Lösung

(x z^{^{'}} + z) (2 z + 1)

Wende Ausklammerungsregel an (VANI):

(a + b) (c + d) = a c + a d + b c + b d

a = x z^{^{'}}, b = z, c = 2 z, d = 1

= x z^{^{^{'}}} \cdot 2 z + x z^{^{^{'}}} \cdot 1 + z \cdot 2 z + z \cdot 1

= 2 x z z^{^{^{'}}} + 1 \cdot x z^{^{^{'}}} + 2 zz + 1 \cdot z

Vereinfache

2 x z z^{^{'}} + 1 \cdot x z^{^{'}} + 2 zz + 1 \cdot z : 2 x z^{1 +^{'}} + x z^{^{'}} + 2 z^{2} + z

= 2 x z^{1 +^{'}} + x z^{^{'}} + 2 z^{2} + z

e x p an d P (1, - 3, 2) Q (2, 1, - 1)

e x p an d \frac{d}{d x} ((x + 1) e^{- x}) + x

e x p an d \frac{2 x ^{2} + 2 x - 4}{( 2 x + 1 ) ^{2}}

e x p an d \frac{( x + 6 ) ^{2}}{4}

e x p an d \frac{4 y - 3 ( x - 1 ) ^{2}}{z + 9}