展開する intersec(t)o(-4)(x-3)^2+10

解

展開する

in t er sec (t) o (- 4) (x - 3)^{2} + 10

- 4 e in t ro x^{2} sec (t) + 24 e in t ro x sec (t) - 36 e in t ro sec (t) + 10

解答ステップ

in t er sec (t) o (- 4) (x - 3)^{2} + 10

括弧を削除する:

(- a) = - a

= - in t er sec (t) o \cdot 4 (x - 3)^{2} + 10

(x - 3)^{2} = x^{2} - 6 x + 9

= - 4 e in t ro sec (t) (x^{2} - 6 x + 9) + 10

= - 4 e in t ro sec (t) (x^{2} - 6 x + 9) + 10

拡張

- in t er sec (t) o \cdot 4 (x^{2} - 6 x + 9) : - 4 e in t ro x^{2} sec (t) + 24 e in t ro x sec (t) - 36 e in t ro sec (t)

= - 4 e in t ro x^{2} sec (t) + 24 e in t ro x sec (t) - 36 e in t ro sec (t) + 10