What is expand A(e^{-b(t-z)}-e^{-g(t-z)}) ?

The solution to expand A(e^{-b(t-z)}-e^{-g(t-z)}) is Ae^{-bt+bz}-Ae^{-tg+zg}

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expand A(e^{-b(t-z)}-e^{-g(t-z)})

expand

A (e^{- b (t - z)} - e^{- g (t - z)})

A e^{- b t + b z} - A e^{- t g + z g}

Solution steps

A (e^{- b (t - z)} - e^{- g (t - z)})

Apply the distributive law:

a (b - c) = ab - a c

a = A, b = e^{- b (t - z)}, c = e^{- g (t - z)}

= A e^{- b (t - z)} - A e^{- g (t - z)}

Simplify

A e^{- b (t - z)} - A e^{- g (t - z)} : A e^{- b t + b z} - A e^{- t g + z g}

= A e^{- b t + b z} - A e^{- t g + z g}

\frac{x ( 1 - x ^{2} ) ^{2}}{2}

(x + 2)^{2} + 3 (x + 1)^{'}

\frac{1}{( z + 3 ) ^{6}}

- \frac{30}{( 3 x + 1 ) ^{3}}

(2 x - 5 y = 7,) (4 x + 2 y = 2)

What is expand A(e^{-b(t-z)}-e^{-g(t-z)}) ?
The solution to expand A(e^{-b(t-z)}-e^{-g(t-z)}) is Ae^{-bt+bz}-Ae^{-tg+zg}