erweitern (u+4)*u^{1/3}du

Lösung

erweitern

(u + 4) \cdot u^{\frac{1}{3}} d u

u^{\frac{4}{3}} d u + 4 u^{\frac{1}{3}} d u

Schritte zur Lösung

(u + 4) u^{\frac{1}{3}} d u

= u^{\frac{1}{3}} (u + 4) d u

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = u^{\frac{1}{3}} d u, b = u, c = 4

= u^{\frac{1}{3}} d uu + u^{\frac{1}{3}} d u \cdot 4

= u u^{\frac{1}{3}} d u + 4 u^{\frac{1}{3}} d u

u u^{\frac{1}{3}} d u = u^{\frac{4}{3}} d u

= u^{\frac{4}{3}} d u + 4 u^{\frac{1}{3}} d u

e x p an d \frac{( x + 6 ) ( x + 4 )}{2}

e x p an d 9 x^{2} (\frac{3}{3 x + 3})

e x p an d \frac{s}{( s ^{2} + 4 ) ( s + 1 )}

e x p an d 3 x (x y - 3) d x + (x^{2} + 2 y) d y

e x p an d \frac{x ^{2} - x - 4}{x ^{2} ( x + 1 )}