展開する a^2+2(b-6)-17(,a=-7,b=2)

解

展開する

a^{2} + 2 (b - 6) - 17 (, a = - 7, b = 2)

a^{2} + 2 b - 12 - 17, a = 17 \cdot 7, b = 2

解答ステップ

a^{2} + 2 (b - 6) - 17 (, a = - 7, b = 2)

= a^{2} + 2 (b - 6) - 17 (, = a - 7 \cdot 2, = b)

拡張

2 (b - 6) : 2 b - 12

= a^{2} + 2 b - 12 - 17 (, a = - 7, b = 2)

拡張

- 17 (, a = - 7, b = 2) : - 17, a = 17 \cdot 7, b = 2

a^{2} + 2 b - 12 - 17, a = 17 \cdot 7, b = 2