展开 (2+3x-4x^2)^5

解答

展开

(2 + 3 x - 4 x^{2})^{5}

- 1024 x^{10} + 3840 x^{9} - 3200 x^{8} - 3360 x^{7} + 4460 x^{6} + 1683 x^{5} - 2230 x^{4} - 840 x^{3} + 400 x^{2} + 240 x + 32

求解步骤

(2 + 3 x - 4 x^{2})^{5}

(2 + 3 x - 4 x^{2})^{5} = (2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2})

= (- 4 x^{2} + 3 x + 2) (- 4 x^{2} + 3 x + 2) (- 4 x^{2} + 3 x + 2) (- 4 x^{2} + 3 x + 2) (- 4 x^{2} + 3 x + 2)

乘开

(2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2}) (2 + 3 x - 4 x^{2}) : - 1024 x^{10} + 3840 x^{9} - 3200 x^{8} - 3360 x^{7} + 4460 x^{6} + 1683 x^{5} - 2230 x^{4} - 840 x^{3} + 400 x^{2} + 240 x + 32

= - 1024 x^{10} + 3840 x^{9} - 3200 x^{8} - 3360 x^{7} + 4460 x^{6} + 1683 x^{5} - 2230 x^{4} - 840 x^{3} + 400 x^{2} + 240 x + 32

e x p an d - 8 d + (- 1) + 9 d^{2} + 8 d

e x p an d \frac{2 x}{x}

e x p an d 2 (d + f^{2} - e^{2})^{2}

e x p an d \frac{a ^{2}}{( x + a ) ^{2} \cdot x}

e x p an d \frac{( y - 5 ) ( y + 1 )}{y}