erweitern (x-3)(x+1)\circ (6x-2)

Lösung

erweitern

(x - 3) (x + 1) \circ (6 x - 2)

6 \circ x^{3} - 14 \circ x^{2} - 14 \circ x + 6 \circ

Schritte zur Lösung

(x - 3) (x + 1) \circ (6 x - 2)

= \circ (x - 3) (x + 1) (6 x - 2)

Multipliziere aus

(x - 3) (x + 1) : x^{2} - 2 x - 3

= \circ (x^{2} - 2 x - 3) (6 x - 2)

Multipliziere aus

(x^{2} - 2 x - 3) (6 x - 2) : 6 x^{3} - 14 x^{2} - 14 x + 6

= \circ (6 x^{3} - 14 x^{2} - 14 x + 6)

Multipliziere aus

\circ (6 x^{3} - 14 x^{2} - 14 x + 6) : 6 \circ x^{3} - 14 \circ x^{2} - 14 \circ x + 6 \circ

= 6 \circ x^{3} - 14 \circ x^{2} - 14 \circ x + 6 \circ

e x p an d \frac{1}{z ( 1 + z )}

e x p an d - \frac{( x + 7 ) ( x - 4 )}{18}

e x p an d \frac{( x + 1 ) ^{2}}{3 x ^{4}}

e x p an d \frac{4 x}{( - x + 1 ) ( x + 1 )}

e x p an d \frac{3 x - 5}{( x - 3 ) ( x ^{2} - 3 x + 2 )}