展开 (((R-S+Scos(θ))))/R

解答

展开

\frac{( ( R - S + S cos ( θ ) ) )}{R}

1 - \frac{S}{R} + \frac{S cos ( θ )}{R}

求解步骤

\frac{R - S + S cos ( θ )}{R}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{R - S + S cos ( θ )}{R} = \frac{R}{R} - \frac{S}{R} + \frac{S cos ( θ )}{R}

= \frac{R}{R} - \frac{S}{R} + \frac{S cos ( θ )}{R}

使用法则

\frac{a}{a} = 1

\frac{R}{R} = 1

= 1 - \frac{S}{R} + \frac{S cos ( θ )}{R}

e x p an d (x + 1) y d x - (y + 1) x d y

e x p an d sech (5.54)

e x p an d \frac{( 3 b + 2 a ) ^{2}}{6 ab}

e x p an d \frac{3 ( y + 1 ) ^{2}}{2}

e x p an d (y - x) e^{\frac{y}{x} + 1}