erweitern ((1-3x)(1+3x))/(9x^2)

Lösung

erweitern

\frac{( 1 - 3 x ) ( 1 + 3 x )}{9 x ^{2}}

\frac{1}{9 x ^{2}} - 1

Schritte zur Lösung

\frac{( 1 - 3 x ) ( 1 + 3 x )}{9 x ^{2}}

Multipliziere aus

(1 - 3 x) (1 + 3 x) : 1 - 9 x^{2}

= \frac{1 - 9 x ^{2}}{9 x ^{2}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 9 x ^{2}}{9 x ^{2}} = \frac{1}{9 x ^{2}} - \frac{9 x ^{2}}{9 x ^{2}}

= \frac{1}{9 x ^{2}} - \frac{9 x ^{2}}{9 x ^{2}}

Wende Regel an

\frac{a}{a} = 1

\frac{9 x ^{2}}{9 x ^{2}} = 1

= \frac{1}{9 x ^{2}} - 1

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