zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

solvefor x,kx^2-3kx+9=0

解答

x, k x^{2} - 3 k x + 9 = 0

解答

x = \frac{3 k + 3 k ( k - 4 )}{2 k}, x = \frac{3 k - 3 k ( k - 4 )}{2 k}; k \neq = 0

求解步骤

k x^{2} - 3 k x + 9 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 3 k ) \pm ( - 3 k ) ^{2} - 4 k \cdot 9}{2 k}

化简

(- 3 k)^{2} - 4 k \cdot 9 : 3 k (k - 4)

x_{1, 2} = \frac{- ( - 3 k ) \pm 3 k ( k - 4 )}{2 k}; k \neq = 0

将解分隔开

x_{1} = \frac{- ( - 3 k ) + 3 k ( k - 4 )}{2 k}, x_{2} = \frac{- ( - 3 k ) - 3 k ( k - 4 )}{2 k}

x = \frac{- ( - 3 k ) + 3 k ( k - 4 )}{2 k} : \frac{3 k + 3 k ( k - 4 )}{2 k}

x = \frac{- ( - 3 k ) - 3 k ( k - 4 )}{2 k} : \frac{3 k - 3 k ( k - 4 )}{2 k}

二次方程组的解是:

x = \frac{3 k + 3 k ( k - 4 )}{2 k}, x = \frac{3 k - 3 k ( k - 4 )}{2 k}; k \neq = 0

作图

流行的例子

5 y^{2} - 2 = - 9 y

2 (3 x - 1)^{2} = 162

(x-6)^2+5(x-6)=3(x-1)^2

(x - 6)^{2} + 5 (x - 6) = 3 (x - 1)^{2}

x^{2} + 2 x + 1 = 5 x + 6

(x+5)(x+3)=5x+25

(x + 5) (x + 3) = 5 x + 25