zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

x^2-2ax=-(a^2-b^2)

解答

x^{2} - 2 a x = - (a^{2} - b^{2})

解答

x = a + b, x = a - b

求解步骤

x^{2} - 2 a x = - (a^{2} - b^{2})

展开

- (a^{2} - b^{2}) : - a^{2} + b^{2}

x^{2} - 2 a x = - a^{2} + b^{2}

将

b^{2}

para o lado esquerdo

x^{2} - 2 a x - b^{2} = - a^{2}

将

a^{2}

para o lado esquerdo

x^{2} - 2 a x - b^{2} + a^{2} = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 \cdot 1 \cdot ( - b ^{2} + a ^{2} )}{2 \cdot 1}

化简

(- 2 a)^{2} - 4 \cdot 1 \cdot (- b^{2} + a^{2}) : 2 b

x_{1, 2} = \frac{- ( - 2 a ) \pm 2 b}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 2 a ) + 2 b}{2 \cdot 1}, x_{2} = \frac{- ( - 2 a ) - 2 b}{2 \cdot 1}

x = \frac{- ( - 2 a ) + 2 b}{2 \cdot 1} : a + b

x = \frac{- ( - 2 a ) - 2 b}{2 \cdot 1} : a - b

二次方程组的解是:

x = a + b, x = a - b

作图

流行的例子

6 v^{2} - 30 = 0

x^{2} + 3 x (x - 2) = 5

completesquare 3x-2x^2=7

co m pl e t es q u a re 3 x - 2 x^{2} = 7

solvefor t,y= 1/2 at^2

so l v e f or t, y = \frac{1}{2} a t^{2}

(x + 2)^{2} = 11