k^2-k=0

解

k^{2} - k = 0

k = 1, k = 0

解答ステップ

k^{2} - k = 0

解くとthe二次式

k_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

k_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

解を分離する

k_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, k_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

k = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

k = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

二次equationの解:

k = 1, k = 0