What are the solutions to the equation 5-2x^2=4x ?

The solutions to the equation 5-2x^2=4x are x=-(2+sqrt(14))/2 ,x=(sqrt(14)-2)/2

Find the zeros of 5-2x^2=4x

The zeros of 5-2x^2=4x are x=-(2+sqrt(14))/2 ,x=(sqrt(14)-2)/2

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5 - 2 x^{2} = 4 x

x = - \frac{2 + 14}{2}, x = \frac{14 - 2}{2}

Decimal

x = - 2.87082 \dots, x = 0.87082 \dots

Solution steps

5 - 2 x^{2} = 4 x

Move

4 x

to the left side

5 - 2 x^{2} - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 5 = 214

x_{1, 2} = \frac{- ( - 4 ) \pm 2 14}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 14}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 2 14}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 2 14}{2 ( - 2 )} : - \frac{2 + 14}{2}

x = \frac{- ( - 4 ) - 2 14}{2 ( - 2 )} : \frac{14 - 2}{2}

The solutions to the quadratic equation are:

x = - \frac{2 + 14}{2}, x = \frac{14 - 2}{2}

x^{2} + 8 = - 41

28 = x^{2} - 4 x + 3 x - 2

- 6 - 12 n^{2} = - 396

m^{2} + 4 m - 3 = 0

(7 + 2 x) (3 + 2 x) = 77

What are the solutions to the equation 5-2x^2=4x ?
The solutions to the equation 5-2x^2=4x are x=-(2+sqrt(14))/2 ,x=(sqrt(14)-2)/2
Find the zeros of 5-2x^2=4x
The zeros of 5-2x^2=4x are x=-(2+sqrt(14))/2 ,x=(sqrt(14)-2)/2