zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

(x+2)^2=x^2+(x-2)^2

解答

(x + 2)^{2} = x^{2} + (x - 2)^{2}

解答

x = 0, x = 8

求解步骤

(x + 2)^{2} = x^{2} + (x - 2)^{2}

展开

(x + 2)^{2} : x^{2} + 4 x + 4

展开

x^{2} + (x - 2)^{2} : 2 x^{2} - 4 x + 4

x^{2} + 4 x + 4 = 2 x^{2} - 4 x + 4

将

4

para o lado esquerdo

x^{2} + 4 x = 2 x^{2} - 4 x

将

4 x

para o lado esquerdo

x^{2} + 8 x = 2 x^{2}

将

2 x^{2}

para o lado esquerdo

- x^{2} + 8 x = 0

使用求根公式求解

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 1 )}

将解分隔开

x_{1} = \frac{- 8 + 8}{2 ( - 1 )}, x_{2} = \frac{- 8 - 8}{2 ( - 1 )}

x = \frac{- 8 + 8}{2 ( - 1 )} : 0

x = \frac{- 8 - 8}{2 ( - 1 )} : 8

二次方程组的解是:

x = 0, x = 8

作图

流行的例子

x^{2} + 5 x = - 16

(x^{2} - 5 x + 6) = 0

0 = - x^{2} - 2 x

- 4 x^{2} + 14 x - 12 = 0

πa = \frac{1}{2} π r^{2}