5x^2-25x=0

解

5 x^{2} - 25 x = 0

x = 5, x = 0

解答ステップ

5 x^{2} - 25 x = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 25)^{2} - 4 \cdot 5 \cdot 0 = 25

x_{1, 2} = \frac{- ( - 25 ) \pm 25}{2 \cdot 5}

解を分離する

x_{1} = \frac{- ( - 25 ) + 25}{2 \cdot 5}, x_{2} = \frac{- ( - 25 ) - 25}{2 \cdot 5}

x = \frac{- ( - 25 ) + 25}{2 \cdot 5} : 5

x = \frac{- ( - 25 ) - 25}{2 \cdot 5} : 0

二次equationの解:

x = 5, x = 0