x^2-25x+156=0

解

x^{2} - 25 x + 156 = 0

x = 13, x = 12

解答ステップ

x^{2} - 25 x + 156 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 156}{2 \cdot 1}

(- 25)^{2} - 4 \cdot 1 \cdot 156 = 1

x_{1, 2} = \frac{- ( - 25 ) \pm 1}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 25 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 25 ) - 1}{2 \cdot 1}

x = \frac{- ( - 25 ) + 1}{2 \cdot 1} : 13

x = \frac{- ( - 25 ) - 1}{2 \cdot 1} : 12

二次equationの解:

x = 13, x = 12