3q^2-300q-112500=0

解

3 q^{2} - 300 q - 112500 = 0

q = 250, q = - 150

解答ステップ

3 q^{2} - 300 q - 112500 = 0

解くとthe二次式

q_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 3 ( - 112500 )}{2 \cdot 3}

(- 300)^{2} - 4 \cdot 3 (- 112500) = 1200

q_{1, 2} = \frac{- ( - 300 ) \pm 1200}{2 \cdot 3}

解を分離する

q_{1} = \frac{- ( - 300 ) + 1200}{2 \cdot 3}, q_{2} = \frac{- ( - 300 ) - 1200}{2 \cdot 3}

q = \frac{- ( - 300 ) + 1200}{2 \cdot 3} : 250

q = \frac{- ( - 300 ) - 1200}{2 \cdot 3} : - 150

二次equationの解:

q = 250, q = - 150