solvefor x,-2x^2-5x+27=0

解

x, - 2 x^{2} - 5 x + 27 = 0

x = - \frac{5 + 241}{4}, x = \frac{241 - 5}{4}

十進法表記

x = - 5.13104 \dots, x = 2.63104 \dots

解答ステップ

- 2 x^{2} - 5 x + 27 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 27}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 27 = 241

x_{1, 2} = \frac{- ( - 5 ) \pm 241}{2 ( - 2 )}

解を分離する

x_{1} = \frac{- ( - 5 ) + 241}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 241}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 241}{2 ( - 2 )} : - \frac{5 + 241}{4}

x = \frac{- ( - 5 ) - 241}{2 ( - 2 )} : \frac{241 - 5}{4}

二次equationの解:

x = - \frac{5 + 241}{4}, x = \frac{241 - 5}{4}