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受欢迎的代数 >

solvefor x,x^2+4kx+2x+4k+2=0

解答

x, x^{2} + 4 k x + 2 x + 4 k + 2 = 0

解答

x = - 2 k - 1 + 4 k^{2} - 1, x = - 2 k - 4 k^{2} - 1 - 1

求解步骤

x^{2} + 4 k x + 2 x + 4 k + 2 = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} + (4 k + 2) x + 4 k + 2 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 4 k + 2 ) \pm ( 4 k + 2 ) ^{2} - 4 \cdot 1 \cdot ( 4 k + 2 )}{2 \cdot 1}

化简

(4 k + 2)^{2} - 4 \cdot 1 \cdot (4 k + 2) : 2 4 k^{2} - 1

x_{1, 2} = \frac{- ( 4 k + 2 ) \pm 2 4 k ^{2} - 1}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( 4 k + 2 ) + 2 4 k ^{2} - 1}{2 \cdot 1}, x_{2} = \frac{- ( 4 k + 2 ) - 2 4 k ^{2} - 1}{2 \cdot 1}

x = \frac{- ( 4 k + 2 ) + 2 4 k ^{2} - 1}{2 \cdot 1} : - 2 k - 1 + 4 k^{2} - 1

x = \frac{- ( 4 k + 2 ) - 2 4 k ^{2} - 1}{2 \cdot 1} : - 2 k - 4 k^{2} - 1 - 1

二次方程组的解是:

x = - 2 k - 1 + 4 k^{2} - 1, x = - 2 k - 4 k^{2} - 1 - 1

作图

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