What are the solutions to the equation l^2-5l-36=0 ?

The solutions to the equation l^2-5l-36=0 are l=9,l=-4

Find the zeros of l^2-5l-36=0

The zeros of l^2-5l-36=0 are l=9,l=-4

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l^{2} - 5 l - 36 = 0

l = 9, l = - 4

Solution steps

l^{2} - 5 l - 36 = 0

Solve with the quadratic formula

l_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 36) = 13

l_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

l_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, l_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

l = \frac{- ( - 5 ) + 13}{2 \cdot 1} : 9

l = \frac{- ( - 5 ) - 13}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

l = 9, l = - 4

12 x^{2} + 163 x + 15 = 0

1.002 x^{2} - 11.01 x + 0.01265 = 0

5 x^{2} + 3 = 28

(3 x + 6)^{2} - 18 = 0

x, 2 x^{2} - 3 x - 14 = 0

What are the solutions to the equation l^2-5l-36=0 ?
The solutions to the equation l^2-5l-36=0 are l=9,l=-4
Find the zeros of l^2-5l-36=0
The zeros of l^2-5l-36=0 are l=9,l=-4