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人気のある代数 >

solvefor x,f=x^2-3x+1f(1)

解

解く

x, f = x^{2} - 3 x + 1 f (1)

解

x = \frac{3 + 9 - 4 ( f ( 1 ) - f )}{2}, x = \frac{3 - 9 - 4 ( f ( 1 ) - f )}{2}

解答ステップ

f = x^{2} - 3 x + 1 \cdot f (1)

改良

f = x^{2} - 3 x + f (1)

辺を交換する

x^{2} - 3 x + f (1) = f

f

を左側に移動します

x^{2} - 3 x + f (1) - f = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( f ( 1 ) - f )}{2 \cdot 1}

簡素化

(- 3)^{2} - 4 \cdot 1 \cdot (f (1) - f) : 9 - 4 (f (1) - f)

x_{1, 2} = \frac{- ( - 3 ) \pm 9 - 4 ( f ( 1 ) - f )}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 3 ) + 9 - 4 ( f ( 1 ) - f )}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 9 - 4 ( f ( 1 ) - f )}{2 \cdot 1}

x = \frac{- ( - 3 ) + 9 - 4 ( f ( 1 ) - f )}{2 \cdot 1} : \frac{3 + 9 - 4 ( f ( 1 ) - f )}{2}

x = \frac{- ( - 3 ) - 9 - 4 ( f ( 1 ) - f )}{2 \cdot 1} : \frac{3 - 9 - 4 ( f ( 1 ) - f )}{2}

二次equationの解:

x = \frac{3 + 9 - 4 ( f ( 1 ) - f )}{2}, x = \frac{3 - 9 - 4 ( f ( 1 ) - f )}{2}

グラフ

人気の例

x^{2} + x^{2} = 14

x^{2} - 11 x = 60

solvefor x,x^2y-2x-9y-1=0

so l v e f or x, x^{2} y - 2 x - 9 y - 1 = 0

x^{2} + 4 x = 30 x

3(x-1)(x+2)=x-7

3 (x - 1) (x + 2) = x - 7