What are the solutions to the equation 3(x-5)^2=27 ?

The solutions to the equation 3(x-5)^2=27 are x=8,x=2

Find the zeros of 3(x-5)^2=27

The zeros of 3(x-5)^2=27 are x=8,x=2

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3 (x - 5)^{2} = 27

x = 8, x = 2

Solution steps

3 (x - 5)^{2} = 27

Divide both sides by

3

(x - 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 9 : x = 8

Solve

x - 5 = - 9 : x = 2

The solutions to the quadratic equation are:

x = 8, x = 2

7 x^{2} - 9 x - 8 = 0

x^{2} + 2 x + \frac{1}{2} = 0

(4 x - 1)^{2} = 27

k^{2} + 12 (- 2) = k (- 2)

120 = x^{2} - 1

What are the solutions to the equation 3(x-5)^2=27 ?
The solutions to the equation 3(x-5)^2=27 are x=8,x=2
Find the zeros of 3(x-5)^2=27
The zeros of 3(x-5)^2=27 are x=8,x=2