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人気のある代数 >

solvefor x,f=x^2+mx+3

解

解く

x, f = x^{2} + m x + 3

解

x = \frac{- m + m ^{2} - 4 ( 3 - f )}{2}, x = \frac{- m - m ^{2} - 4 ( 3 - f )}{2}

解答ステップ

f = x^{2} + m x + 3

辺を交換する

x^{2} + m x + 3 = f

f

を左側に移動します

x^{2} + m x + 3 - f = 0

解くとthe二次式

x_{1, 2} = \frac{- m \pm m ^{2} - 4 \cdot 1 \cdot ( 3 - f )}{2 \cdot 1}

簡素化

m^{2} - 4 \cdot 1 \cdot (3 - f) : m^{2} - 4 (3 - f)

x_{1, 2} = \frac{- m \pm m ^{2} - 4 ( 3 - f )}{2 \cdot 1}

解を分離する

x_{1} = \frac{- m + m ^{2} - 4 ( 3 - f )}{2 \cdot 1}, x_{2} = \frac{- m - m ^{2} - 4 ( 3 - f )}{2 \cdot 1}

x = \frac{- m + m ^{2} - 4 ( 3 - f )}{2 \cdot 1} : \frac{- m + m ^{2} - 4 ( 3 - f )}{2}

x = \frac{- m - m ^{2} - 4 ( 3 - f )}{2 \cdot 1} : \frac{- m - m ^{2} - 4 ( 3 - f )}{2}

二次equationの解:

x = \frac{- m + m ^{2} - 4 ( 3 - f )}{2}, x = \frac{- m - m ^{2} - 4 ( 3 - f )}{2}

グラフ

人気の例

(x + 1)^{2} = 13

(x + 1)^{2} = 15

2 = 3 x^{2} - x + 2

x^2-2.459x+1.5=0

x^{2} - 2.459 x + 1.5 = 0

quadraticformula 2x^2-6x+1=0

q u a d r a t i c f or m u l a 2 x^{2} - 6 x + 1 = 0