quadraticformula 2x^2-6x+1=0

解

2 x^{2} - 6 x + 1 = 0

x = \frac{3 + 7}{2}, x = \frac{3 - 7}{2}

十進法表記

x = 2.82287 \dots, x = 0.17712 \dots

解答ステップ

2 x^{2} - 6 x + 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 \cdot 1 = 27

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7}{2 \cdot 2}

解を分離する

x_{1} = \frac{- ( - 6 ) + 2 7}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 7}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 7}{2 \cdot 2} : \frac{3 + 7}{2}

x = \frac{- ( - 6 ) - 2 7}{2 \cdot 2} : \frac{3 - 7}{2}

二次equationの解:

x = \frac{3 + 7}{2}, x = \frac{3 - 7}{2}