What are the solutions to the equation a^2-12a=-27 ?

The solutions to the equation a^2-12a=-27 are a=9,a=3

Find the zeros of a^2-12a=-27

The zeros of a^2-12a=-27 are a=9,a=3

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a^{2} - 12 a = - 27

a = 9, a = 3

Solution steps

a^{2} - 12 a = - 27

Move

27

to the left side

a^{2} - 12 a + 27 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 27 = 6

a_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 1}, a_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 1}

a = \frac{- ( - 12 ) + 6}{2 \cdot 1} : 9

a = \frac{- ( - 12 ) - 6}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

a = 9, a = 3

4 x^{2} + 232 = - 64 x

- 16 x^{2} + 12 x + 40 = 0

4 x^{2} + 1 - 5 = 0

2 (x - 6)^{2} - 2 = 30

D (- 1) = x^{2} - 2 x - 1

What are the solutions to the equation a^2-12a=-27 ?
The solutions to the equation a^2-12a=-27 are a=9,a=3
Find the zeros of a^2-12a=-27
The zeros of a^2-12a=-27 are a=9,a=3