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人気のある代数 >

solvefor x,f(x+c)=8(x+c)^2+4

解

解く

x, f (x + c) = 8 (x + c)^{2} + 4

解

x = \frac{- 16 c + f + f ^{2} - 128}{16}, x = \frac{- 16 c + f - f ^{2} - 128}{16}

解答ステップ

f (x + c) = 8 (x + c)^{2} + 4

拡張

f (x + c) : x f + c f

拡張

8 (x + c)^{2} + 4 : 8 x^{2} + 16 c x + 8 c^{2} + 4

x f + c f = 8 x^{2} + 16 c x + 8 c^{2} + 4

辺を交換する

8 x^{2} + 16 c x + 8 c^{2} + 4 = x f + c f

c f

を左側に移動します

8 x^{2} + 16 c x + 8 c^{2} + 4 - c f = x f

x f

を左側に移動します

8 x^{2} + 16 c x + 8 c^{2} + 4 - c f - x f = 0

標準的な形式で書く

a x^{2} + b x + c = 0

8 x^{2} + (16 c - f) x + 8 c^{2} + 4 - c f = 0

解くとthe二次式

x_{1, 2} = \frac{- ( 16 c - f ) \pm ( 16 c - f ) ^{2} - 4 \cdot 8 ( 8 c ^{2} + 4 - c f )}{2 \cdot 8}

簡素化

(16 c - f)^{2} - 4 \cdot 8 (8 c^{2} + 4 - c f) : f^{2} - 128

x_{1, 2} = \frac{- ( 16 c - f ) \pm f ^{2} - 128}{2 \cdot 8}

解を分離する

x_{1} = \frac{- ( 16 c - f ) + f ^{2} - 128}{2 \cdot 8}, x_{2} = \frac{- ( 16 c - f ) - f ^{2} - 128}{2 \cdot 8}

x = \frac{- ( 16 c - f ) + f ^{2} - 128}{2 \cdot 8} : \frac{- 16 c + f + f ^{2} - 128}{16}

x = \frac{- ( 16 c - f ) - f ^{2} - 128}{2 \cdot 8} : \frac{- 16 c + f - f ^{2} - 128}{16}

二次equationの解:

x = \frac{- 16 c + f + f ^{2} - 128}{16}, x = \frac{- 16 c + f - f ^{2} - 128}{16}

グラフ

人気の例

49k^2-231k-70=0

49 k^{2} - 231 k - 70 = 0

ax^2+ax+7=3x^2-x+5a

a x^{2} + a x + 7 = 3 x^{2} - x + 5 a

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mn x^{2} - (m^{2} - n^{2}) x + mn = 0

5 x^{2} + 7 x - 8 = 0

0 = 2 x^{2} - x + 3