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人気のある代数 >

solvefor x,f=(2m-1)x^2-10x-m

解

解く

x, f = (2 m - 1) x^{2} - 10 x - m

解

x = \frac{5 + - ( 2 m - 1 ) ( - f - m ) + 25}{2 m - 1}, x = \frac{5 - - ( 2 m - 1 ) ( - f - m ) + 25}{2 m - 1}; m \neq = \frac{1}{2}

解答ステップ

f = (2 m - 1) x^{2} - 10 x - m

辺を交換する

(2 m - 1) x^{2} - 10 x - m = f

f

を左側に移動します

(2 m - 1) x^{2} - 10 x - m - f = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( 2 m - 1 ) ( - m - f )}{2 ( 2 m - 1 )}

簡素化

(- 10)^{2} - 4 (2 m - 1) (- m - f) : 2 25 - (- 1 + 2 m) (- m - f)

x_{1, 2} = \frac{- ( - 10 ) \pm 2 25 - ( - 1 + 2 m ) ( - m - f )}{2 ( 2 m - 1 )}; m \neq = \frac{1}{2}

解を分離する

x_{1} = \frac{- ( - 10 ) + 2 25 - ( - 1 + 2 m ) ( - m - f )}{2 ( 2 m - 1 )}, x_{2} = \frac{- ( - 10 ) - 2 25 - ( - 1 + 2 m ) ( - m - f )}{2 ( 2 m - 1 )}

x = \frac{- ( - 10 ) + 2 25 - ( - 1 + 2 m ) ( - m - f )}{2 ( 2 m - 1 )} : \frac{5 + - ( 2 m - 1 ) ( - f - m ) + 25}{2 m - 1}

x = \frac{- ( - 10 ) - 2 25 - ( - 1 + 2 m ) ( - m - f )}{2 ( 2 m - 1 )} : \frac{5 - - ( 2 m - 1 ) ( - f - m ) + 25}{2 m - 1}

二次equationの解:

x = \frac{5 + - ( 2 m - 1 ) ( - f - m ) + 25}{2 m - 1}, x = \frac{5 - - ( 2 m - 1 ) ( - f - m ) + 25}{2 m - 1}; m \neq = \frac{1}{2}

グラフ

人気の例

- 3 c + 2 + c^{2} = 0

t^{2} - t - 4 = 0

k^{2} + 8 k = 0

x^{2} = 208

0 = 4 x^{2} + 16 x