(AX+B)/X =(CX)/D

解

\frac{A X + B}{X} = \frac{CX}{D}

X = \frac{A D + A ^{2} D ^{2} + 4 BC D}{2 C}, X = \frac{A D - A ^{2} D ^{2} + 4 BC D}{2 C}; D \neq = 0, C \neq = 0

解答ステップ

\frac{A X + B}{X} = \frac{CX}{D}

たすき掛け

(A X + B) D = C X^{2}; D \neq = 0

解く

(A X + B) D = C X^{2} : X = \frac{A D + A ^{2} D ^{2} + 4 BC D}{2 C}, X = \frac{A D - A ^{2} D ^{2} + 4 BC D}{2 C}; C \neq = 0

X = \frac{A D + A ^{2} D ^{2} + 4 BC D}{2 C}, X = \frac{A D - A ^{2} D ^{2} + 4 BC D}{2 C}; D \neq = 0, C \neq = 0