7^{x+2}=98

Lösung

7^{x + 2} = 98

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

Dezimale

x = 0.35620 \dots

Schritte zur Lösung

7^{x + 2} = 98

Wende Exponentenregel an

(x + 2) ln (7) = ln (98)

Löse

(x + 2) ln (7) = ln (98) : x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

so l v e f or x, e^{a x} = C e^{b x}

5^{x} - 5^{5 - x} = 150

so l v e f or y, x = e^{y}

5^{2 x} - 2 \cdot 5^{x} - 15 = 0

e^{2 x} = 0