4^{2x-1}=8^{x+3}

Lösung

4^{2 x - 1} = 8^{x + 3}

x = 11

Schritte zur Lösung

4^{2 x - 1} = 8^{x + 3}

Wende Exponentenregel an

2 (2 x - 1) = 3 (x + 3)

Löse

2 (2 x - 1) = 3 (x + 3) : x = 11

x = 11

3^{x + 2} = 7

3^{x} = (\frac{1}{3})^{x + 1}

8 1^{x - 1} = 2 7^{x}

4^{x} - 3 \cdot 2^{x + 1} + 8 = 0

5^{3 - 2 x} = 5^{- x}