0.2^{x+1}=sqrt(125)

Lösung

0. 2^{x + 1} = 125

x = - \frac{5}{2}

Dezimale

x = - 2.5

Schritte zur Lösung

0. 2^{x + 1} = 125

Wende Exponentenregel an

- (x + 1) = \frac{3}{2}

Löse

- (x + 1) = \frac{3}{2} : x = - \frac{5}{2}

x = - \frac{5}{2}

7. 5^{3 r} = 2.6

4^{x} - 3 \cdot 2^{x} + 2 = 0

e^{x} + 1 = 6 e^{- x}

\frac{3 2}{8} = 2^{m}

254 = 2^{x}