4^x=5^{2x+1}

Lösung

4^{x} = 5^{2 x + 1}

x = \frac{ln ( 5 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

Dezimale

x = - 0.87823 \dots

Schritte zur Lösung

4^{x} = 5^{2 x + 1}

Wende Exponentenregel an

x ln (4) = (2 x + 1) ln (5)

Löse

x ln (4) = (2 x + 1) ln (5) : x = \frac{ln ( 5 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

x = \frac{ln ( 5 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

x^{x^{3}} = 2^{2}

so l v e f or x, e^{x} + e^{- x} = 3

so l v e f or k, n = 2^{k}

3^{x} = 19

9^{b^{3} - 1} = 81