3^{x+2}=5^{x-1}

Lösung

3^{x + 2} = 5^{x - 1}

x = \frac{ln ( 45 )}{ln ( 5 ) - ln ( 3 )}

Dezimale

x = 7.45198 \dots

Schritte zur Lösung

3^{x + 2} = 5^{x - 1}

Wende Exponentenregel an

(x + 2) ln (3) = (x - 1) ln (5)

Löse

(x + 2) ln (3) = (x - 1) ln (5) : x = \frac{ln ( 45 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{ln ( 45 )}{ln ( 5 ) - ln ( 3 )}

x^{3} = 3^{x}

e^{l n (x)} = 4

5^{x + 3} \cdot 5^{2 x - 4} = 125

2 \cdot 3^{4 t} = 5^{- t}

4^{x + 2} = 64