81^{5x-2}=27^{x+4}

Lösung

8 1^{5 x - 2} = 2 7^{x + 4}

x = \frac{20}{17}

Dezimale

x = 1.17647 \dots

Schritte zur Lösung

8 1^{5 x - 2} = 2 7^{x + 4}

Wende Exponentenregel an

4 (5 x - 2) = 3 (x + 4)

Löse

4 (5 x - 2) = 3 (x + 4) : x = \frac{20}{17}

x = \frac{20}{17}

4^{x - 1} = 5

so l v e f or a, (x^{a})^{b} = b x^{a}

10000 = 40000 e^{- 0.06 t}

1 1^{x} = 1 1^{4} \cdot 1 1^{5}

lo g_{3} (7^{5 x}) = 10