What is the answer to 4^x=20 ?

The answer to 4^x=20 is x=(ln(20))/(2ln(2))

The solution is x=(ln(20))/(2ln(2))

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4^x=20

4^{x} = 20

x = \frac{ln ( 20 )}{2 ln ( 2 )}

Decimal Notation

x = 2.16096 \dots

Solution steps

4^{x} = 20

Apply exponent rules

x ln (4) = ln (20)

Solve

x ln (4) = ln (20) : x = \frac{ln ( 20 )}{2 ln ( 2 )}

x = \frac{ln ( 20 )}{2 ln ( 2 )}

2^{2 x + 3} = 3^{3 x}

5^{x} - 75 \cdot 5^{- x} = 22

1.0 4^{x} = 2

5^{x} = 5^{3} \cdot 5^{8}

- 6 \cdot 2^{0.1 x} = - 100