(1/3)^{x+2}=3^{x-1}

Lösung

(\frac{1}{3})^{x + 2} = 3^{x - 1}

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

(\frac{1}{3})^{x + 2} = 3^{x - 1}

Wende Exponentenregel an

- (x + 2) = x - 1

Löse

- (x + 2) = x - 1 : x = - \frac{1}{2}

x = - \frac{1}{2}

2^{x^{2} - x - 3} = \frac{1}{2}

3^{8} = 9^{x}

9^{2 x - 1} = 3^{- x + 8}

4^{2 x - 1} = 3^{x + 2}

e^{x} - 7 = 2 e^{- x}