(1/4)^{x+1}=32

Lösung

(\frac{1}{4})^{x + 1} = 32

x = - \frac{7}{2}

Dezimale

x = - 3.5

Schritte zur Lösung

(\frac{1}{4})^{x + 1} = 32

Wende Exponentenregel an

- 2 (x + 1) = 5

Löse

- 2 (x + 1) = 5 : x = - \frac{7}{2}

x = - \frac{7}{2}

3^{x} = 24

\frac{4 ^{6}}{4 ^{x}} = 4^{0}

2^{2 y} \cdot 2^{2 y - 12} = 16

so l v e f or x, 5^{4 x} = m + 1

4^{x} + 2^{x + 1} = 80