20^{x-9}=12

Lösung

2 0^{x - 9} = 12

x = \frac{ln ( 12 )}{ln ( 20 )} + 9

Dezimale

x = 9.82948 \dots

Schritte zur Lösung

2 0^{x - 9} = 12

Wende Exponentenregel an

(x - 9) ln (20) = ln (12)

Löse

(x - 9) ln (20) = ln (12) : x = \frac{ln ( 12 )}{ln ( 20 )} + 9

x = \frac{ln ( 12 )}{ln ( 20 )} + 9

1 0^{\frac{3 x - 1}{2 x + 1}} = 100

0.2 e^{4 x} - 0.1 e^{- 3 x} = 0

(1 4^{3 x + 1}) (8^{2 x + 3}) = 7

5^{x} = 22

5^{x} = 23