4^x+2^{1+2x}=40

Lösung

4^{x} + 2^{1 + 2 x} = 40

x = \frac{ln ( \frac{40}{3} )}{2 ln ( 2 )}

Dezimale

x = 1.86848 \dots

Schritte zur Lösung

4^{x} + 2^{1 + 2 x} = 40

Wende Exponentenregel an

2 x ln (2) = ln (\frac{40}{3})

Löse

2 x ln (2) = ln (\frac{40}{3}) : x = \frac{ln ( \frac{40}{3} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{40}{3} )}{2 ln ( 2 )}

3^{2 x} - 3^{x} - 6 = 0

3^{x} + 3^{x + 2} = 90

1 0^{x} = 31

1 0^{x} = 87

2 5^{3 x + 2} = 125