e^{2x-1}=4

Lösung

e^{2 x - 1} = 4

x = \frac{2 ln ( 2 ) + 1}{2}

Dezimale

x = 1.19314 \dots

Schritte zur Lösung

e^{2 x - 1} = 4

Wende Exponentenregel an

2 x - 1 = ln (4)

Löse

2 x - 1 = ln (4) : x = \frac{2 ln ( 2 ) + 1}{2}

x = \frac{2 ln ( 2 ) + 1}{2}

2^{x} + 2^{x + 1} = 12

1.4 = 1. 1^{x}

2^{x + 2} = \frac{1}{32}

lo g_{7} (5^{2 x}) = 18

9^{4 x} = 27